4(1[v-1]1)=-[3]v+38

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Solution for 4(1[v-1]1)=-[3]v+38 equation:


Simplifying
4(1[v + -1] * 1) = -1[3] * v + 38

Reorder the terms:
4(1[-1 + v] * 1) = -1[3] * v + 38

Reorder the terms for easier multiplication:
4(1 * 1[-1 + v]) = -1[3] * v + 38

Multiply 1 * 1
4(1[-1 + v]) = -1[3] * v + 38
4([-1 * 1 + v * 1]) = -1[3] * v + 38
4([-1 + 1v]) = -1[3] * v + 38
(-1 * 4 + 1v * 4) = -1[3] * v + 38
(-4 + 4v) = -1[3] * v + 38

Multiply -1 * 3
-4 + 4v = -3v + 38

Reorder the terms:
-4 + 4v = 38 + -3v

Solving
-4 + 4v = 38 + -3v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '3v' to each side of the equation.
-4 + 4v + 3v = 38 + -3v + 3v

Combine like terms: 4v + 3v = 7v
-4 + 7v = 38 + -3v + 3v

Combine like terms: -3v + 3v = 0
-4 + 7v = 38 + 0
-4 + 7v = 38

Add '4' to each side of the equation.
-4 + 4 + 7v = 38 + 4

Combine like terms: -4 + 4 = 0
0 + 7v = 38 + 4
7v = 38 + 4

Combine like terms: 38 + 4 = 42
7v = 42

Divide each side by '7'.
v = 6

Simplifying
v = 6

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